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第章线性时不变系统的时域分析2习题二3d d3d2d
2.1-1⑷2券“⑴+5条“t+5焉“⑴+32it=2焉%⑴焉%⑴+.tvv C Uv vL XV LvCUvC vvv强⑴+乳⑴+疝⑴齐⑴255+3*23=*〃3〃2〃d2充劭+25—u t+5—u t+3—u t=2—xt000j2j d2db2—^0+7-i^t+51t=2—/t+-/t+2/t v»L vvL L4*L v*L急⑴+272t+5i20+6»t22—u t+7—u t+5u t=6/t vvL L000d2d^d,4;77^式+6—iit+4tlt=2—%tdt atat乙d d24^H72+6直Mt+优⑴=2Gxtd2d d2d左劭⑴+46—u t+4aot=2—xt+6—xt+2xt CXC CvL X-C0IX L条为⑴+四修条为⑴+叫卢*2⑴普%⑴=Er%⑴U LUL TTl^TTl2ULrriW
2.2-3l45e.3t_25e-2t-8-t〃Q2-5e-2t+7e-ta«3—3e-2t+2te~2t+5e-tut
2.2-4lge-3t-|e-4t+iut⑵伽小_|e-4t+\e-t〃Q3[2—te-3t—2e-4t]ut
2.2-5ly0+=yO-=l,/0+=32yT=yT=2,y,0+=
22.2-6yt=-2e-3t+1+2e-t t0y t=3e~2t—2e~3t t0ziy t=2e-t—3e-2t+It0zsy团t=-2e-3tt07/t=1+2e-t
2.2-1yn+2-
1.7yn+1+
0.72yn=
0.02xn,y0=0,y1=
0.
32.2-2a yn+2+3yn+l+5yn=xnb yn-4yn-1-5yn-2=3xn+2xn-
12.2-3y7i=2§n1Q Qq
2.2-4yn=282n-—3n-6n--n022⑴目225n0;22n-\n03[2-lnf--2n+2],n0;4l+2n-ln,n0;rm nn14135cos—+2sin—,n0;6-n--+—-2n,n0;z z5y y72n+1-2,n0;8-3n---ln--n-ln,n0;九严+尸
2.2-6yn=|—1——252n02%九=々一1九--2n n0J17fn=-2n n0yiin=-ln-2-2”
02.3-1le-2tut225t—4e-2tut325t-5t+5e-2tut
2.3-2hn=2nun
2.3-3l3n-1-2n^un-1⑵-3n+3一2严-驷⑴348n+2n—
40.5nun113—4yn=xn—-xn+-xn—
12.4-1lil-e-atut2coscot+45°3i[l-e-at-2]ut-2114-[1—cos/rft++1H—[1—cos/rft——171715-2sincDsina681-e-tut-81--2+8e-t-e-3ut-3+8e-3-e-ct-2ut—5rl3]rl9]7-t-l2-t+-ut-2--t-42-t+-ut-5-乙」乙乙-L-乙-t_12_t_3ut_5+—t—42_t ut_
8.
2..
22.4-4co coscoot+5sin cotuto o
2.4-6⑴ut-ug⑵^1-e-2tut-;[1-e-2D]〃t_
12.4-7y t=4二—3e-2tt0x固有响应—e-t--e~2tt032强迫响应-e-4t6瞬态响应:1471——e~l—e~2t—e~4tt326-稳态响应0⑴{”|,吟?2,|,吟2{2,6,12,20,30,42,54,64,58,
2.5-150,40,28,14}
12.5-21{1,233,3,2,1}-32{3,5,6,6,6,3/}-24{321,0,3,21}-
22.5-3ln+lun⑵2—g un33n+1-2n+1un42n+1u-n+2un-15I-4^un-6+1-144nu-n+
52.5-4Xi l*x1=12,4*X4=30,X[6*X6=362X122xi8*X8=30,ll*x11=12,13*x13=02X12X
122.5-55[1-
0.8n+1]un—5[1-
0.8n-2]un—3为偶数为奇数
2.5-6hn={0,n n
2.5-7/in=-
0.5n--
0.3n+-
0.6nl un28811J
2.5-83・3nun+2un—6・2nlin
2.6-1110-4;104Hz;IO4月脉冲/每秒脉冲/每秒
2.6-2l
0.6ms21667。