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名称:砂浆压力试验机砂浆立方体试件抗压强度试验其他名称砂浆压力试验机,砂浆抗压强度试验机,砂浆实验仪器型号DYE-300荣计达产品编号SJ0311000元
一、产品简介设备是我公司升**产品智能仪表可换算压强值,自动换算每组试块的平均值,主要用于测定水泥、砂浆小梁试块的抗压强度之用砂浆压力试验机在电动液压加荷和传感器测力方面都有很大改进,智能仪表显示力值更加稳定不受自然气频的影响,示值灵敏度高,结构紧凑,造型新颖,操作方便,维修简单,运输方便等优点Mortar pressure testing machineis ourcompanys product.The intelligentinstrumentcan convertthe pressurevalue and automatically convertthe averagevalueof eachtest block.It ismainly usedto determinethe compressive strengthof cementand mortartrabecular testblocks.The mortar pressuretesting machinehas beengreatly improvedin termsof electro-hydraulic loadingand sensorforcemeasurement,and theintelligent instrumentshows amore stableforce value.Notaffected bynatural gasfrequency,high indicationsensitivity,compact structure,novel shape,convenient operation,simple maintenance,convenient transportation,etc.
二、技术参数;A大载荷★300KN准确度等**:一**★测力范围★30—300KNA小分辨率★
0.1KN仪表使用电压:★220V±10%电机使用电压:★380V±10%电动机功率:★
0.75KW示值相对误差★±1%油压大压强★A25MPa★外形尺寸840X530X1450mmTechnical parametersof mortarpressure tester;A largeload:300KN★Accuracy etc.**:1**一一Force measurementrange:30300KNA smallresolution:
0.1KN土★Using instrumentvoltage:220V10%Motor usevoltage:380V±10%★Motor power:
0.75KWRelative errorof displayedvalue:±1%★Hydraulic pressureA:25MPa★Dimensions:840X530X1450mm
三、砂浆压力试验机,砂浆抗压强度试验方法采用立方体试件,每组试件个★3★应用黄油等密封材料斜抹试模的外接缝,试模内涂刷薄层机油或脱模剂,将拌制好的砂浆一次性装满砂浆试模,成型方法根据稠度而定当稠度时采用人250mm工振捣成型,当稠度〈时采用振动台振实成型人工振动用捣棒均匀地50mm1由边缘向中按螺旋方式插捣次,插捣过程中如砂浆沉落低于试模口,应随时添25加砂浆,可用油灰刀插捣数次,并用手将试模一边抬高各振动次,〜5mm10mm5使砂浆高出试模顶面机械振动将砂浆一次装满试模,放置到振动台〜6mm8mm2o上,振动时试模不得跳动,振动秒或持续至表面出浆为止;不得过振〜510待表面水分稍干后,将高出试模部分的砂浆沿试模顶面刮去并抹平★★试件制作后应在室温为的环境下静置当气温较底时,可适当延℃20±524±2h,长时间,但不应超过两昼夜,然后对试件进行编号、拆模试件拆模后应立即放入温度为相对湿度为以上的试件拆模后应立即放入温度为℃以上的标准℃20±290%养护室中养护养护期间,试件彼此间隔不小于混合砂标准养护室中养护10mm,浆试件上面应覆盖以防有水滴在试件上★Mortar pressuretesting machine,mortar compressivestrength testmethod Usingcubetest pieces,3test piecesper group.★Apply sealingmaterials suchas butterto obliquelywipe theexternal jointsof the test mold,apply athin layerof engineoil ormold releaseagent to thetest mold,and fillthe mixedmortar with the mortartest moldat onetime.Themolding methoddepends on the consistency.When theconsistency isgreater thanorequal to50,artificial vibrationand compactionare adopted.When theconsistencyis lessthan50,the vibrationtable isused forcompaction.1Artificial vibration:Use atamper toinsert andtamp25times from the edgetothe centerin aspiral manner.If the mortar sinksbelow the test dieduring thetampingprocess,mortar should be addedat anytime,andaputty knifecan be一边〜used fortamping severaltimes.Raise the test moldside by5mm10for高〜5times eachtime,so that the mortaris668above the top surface of thetestdies.2Mechanical vibration:Fill the testmoldwiththe mortar onceandplace iton theshaker.The testmold mustnot jumpduring vibration.The vibrationshouldlast5to10seconds orcontinue until the surfaceis outof slurry.Donot overvibrate.★After thesurface moistureis slightlydry,scrape the mortar thatis higherthanthe testmold alongthetopsurface of the testmold andsmooth it.土★℃After the test pieceis made,it should be leftat roomtemperature205for24±2h.When thetemperature islow,the timecan beappropriately extended,but itshould notexceed twodays andnights.Numbering,demolding.Immediatelyafter dismantlingthetest piece,it shall be placedin a standard curingroom土with atemperature of202°C andrelative humidityof90%or more.Duringcuring,the specimensshould bespaced atleast10mm apartfrom eachother.Thecuring slurryspecimens inastandardsand mixingroom should be coveredto preventwaterfrom drippingonto thespecimens.
四、砂浆立方体试件抗压强度试验应按下列步骤进行砂浆压力试验机★DYE-300试件从养护地点取出后应及时进行试验试验前将试件表面擦试干净,测量尺寸,并检查其外观并据此计算试件的承压面积,如实测尺寸与公称尺寸之差不超过1可按公称尺寸进行计算;mm,★将试件安放在试验机的下压板或下垫板上,试件的承压面应与成型时的顶面垂直,试件中应与试验机下压板或下垫板中对准开动试验机,当上压板与试件或上垫板接近时,调整球座,使接触面均衡受压承压试验应连续而均匀地加荷,加荷速度应为每秒钟砂浆强度不大于时,宜取下限,砂〜
0.2kN
1.5kN5Mpa浆强度大于时,宜取上限,当试件接近破坏而开始迅速变形时,停止调整试5Mpa验机油门,直至试件破坏,然后记录破坏荷载The compressivestrength testof mortar cube specimensshould becarried out★according tothe followingsteps:DYE-300mortarpressure tester The testspecimen shallbe testedin timeafter beingtaken outfromthemaintenance site.Before thetest,wipe thesurfaceof thetest piece clean,measure thesize,andcheck itsappearance.The pressurebearing areaof thetest pieceis calculatedaccordingly.If thedifference betweenthe measuredsize and the nominalsizedoes notexceed1mm,it canbe calculatedaccording tothe nominalsize;★Place thetest pieceonthe lower plateor lowerplate of the testingmachine.The pressurebearing surfaceof thetest piece shouldbeperpendicular tothetop surfaceof thetest machine.Thetest pieceshouldbe inthe lowerplate orlowerplate of thetestmachine,alignment.Start thetestingmachine.When theupperpressure plateis closetothetest pieceor upperplate,adjust theballseat sothatthecontact surfaceis evenlypressed.The pressuretest shouldbe〜continuously anduniformly loaded,and theloading speedshouldbe
0.2kN
1.5kNper secondthelowerlimit shouldbe taken when themortar strength is notgreaterthan5Mpa,and theupper limitshouldbetakenwhenthemortarstrengthisgreaterthan5Mpa Whenapproaching damageand startto deformrapidly,stop adjustingthetester throttleuntilthetestpieceis broken,and thenrecord thedamageload.
五、砂浆压力试验机砂浆立方体抗压强度应按下式计算式中砂浆立方体试件抗压强度⑼Fm,cu=Nu
0.5A fm,cu Mpa;NU试件破坏荷载试件承压面积砂浆立方体试件抗压强度应**至N;A mm2以三个试件测值的算术平均值为倍作为该组试件的砂浆立方体
0.IMpao
1.3f2试件抗压强度平均值**至当三个测值的A大值或小值中如有一个与
0.IMpa oA中间值的差值超过中间值的时,则把大值及小值一并舍除,取中间值作为15%A A该**试件的抗压强度值;如有两个测值与中间值的差值均超过中间值的时,则15%该组试件的试验结果无效The compressivestrength ofthemortar cube ofthemortarpressuretestershallbe calculatedas follows:Fm,cu=Nu
9.
0.5where fm,cu Mortarcube specimencompressivestrengthMpa;NU specimenfailure loadN;A specimenpressure areamm2mortarcubeThecompressive strengthofthetestpieceshallbe**to
0.IMpa.Take thearithmeticmean ofthe measuredvalues ofthe threespecimens as
1.3times f2as theaveragecompressive strengthofthemortarcubespecimens ofthis group**to
0.IMpa.When thedifference betweenthe majorA valueor minorA valueofthethree measuredvaluesexceeds the intermediate valueby morethan15%,the majorA valueandminor Avalue aredivided together,andthemedian valueis takenas thevalue.**The compressivestrength valueofthetestpiece;if thedifference betweenthetwo measuredvalues andtheintermediatevalue exceeds15%oftheintermediatevalue,thetestresults ofthis groupof testpieces areinvalid.。